The line segment is the straight line and it has two points. They are starting point and ending point. The starting point is in the starting place of the line and the ending point is in the ending place of the line. The length of line segment is the distance between the starting point and ending point of a line.
Diagram and formula - Length of line segment:
The formula to find the length of the line segment with two points (x1,y1) and (x2, y2) is
Distance d = `sqrt((x2 - x1)^2 + (y2 - y1)^2)`
Example problems - Length of line segment:
Find the length of line segment and the points are (1,1) and (2, 2).
Solution:
Given , (1,1) and (2, 2).
Let us take (1 ,1 ) as (x1, y1) and (2, 2) as (x2, y2).
The formula is Distance d = `sqrt((x2 - x1)^2 + (y2 - y1)^2)`
Now substitute the given values in the formula.
Distance d = `sqrt((2-1)^2 + (2-1)^2)`
=`sqrt(1^2 + 1^2)`
= `sqrt(1 + 1)`
= `sqrt(2)`
Find the length of line segment and the points are (1,1) and (3, 3).
Solution:
Given , (1,1) and (3, 3).
Let us take (1 ,1 ) as (x1, y1) and (3, 3) as (x2, y2).
The formula is Distance d = `sqrt((x2 - x1)^2 + (y2 - y1)^2)`
Now substitute the given values in the formula.
Distance d = `sqrt((3-1)^2 + (3-1)^2)`
= `sqrt(2^2 + 2^2)`
= `sqrt(4+4)`
= `sqrt(8)` .
= `sqrt(4 * 2)`
= `sqrt(4)` `xx` `sqrt(2)`
= 2 `xx` `sqrt(2)` .
Find the length of line segment and the points are (3,3) and (2, 2).
Solution:
Given , (3,3) and (2, 2).
Let us take (3 ,3 ) as (x1, y1) and (2, 2) as (x2, y2).
The formula is Distance d = `sqrt((x2 - x1)^2 + (y2 - y1)^2)`
Now substitute the given values in the formula.
Distance d = `sqrt((2-3)^2 +(2-3)^2)`
= `sqrt((-1)^2 + (-1)^2)`
= `sqrt(1 + 1)`
= `sqrt(2)` .
Find the length of line segment and the points are (2,2) and (5, 5).
Solution:
Given , (2,2) and (5, 5).
Let us take (2 ,2 ) as (x1, y1) and (5, 5) as (x2, y2).
The formula is Distance d = `sqrt((x2 - x1)^2 + (y2 - y1)^2)`
Now substitute the given values in the formula.
Distance d = `sqrt((5-2)^2 + (5-2)^2)`
= `sqrt(3^2 + 3^2)`
= `sqrt(9+9)`
= `sqrt(18)`
= `sqrt(9 * 2)`
= `sqrt(9)` `xx` `sqrt(2)`
= 3 `xx` `sqrt(2)`
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